# What transition energy corresponds to an absorption line at 460 nm?

Mar 11, 2017

I got 4.3×10^(-19)J

#### Explanation:

We can use Einstein's relationship for the energy:
$E = h f$
Where $f$ is frequency and $h$ is Planck's constant.
In numbers:
E=6.63×10^(-34)*(3×10^8)/(460×10^(-9))=4.3×10^(-19)J

Where:
$f = \left(\text{speed of light")/("wavelength}\right)$