What transition energy corresponds to an absorption line at 460 nm?

1 Answer
Mar 11, 2017

I got #4.3×10^(-19)J#

Explanation:

We can use Einstein's relationship for the energy:
#E=hf#
Where #f# is frequency and #h# is Planck's constant.
In numbers:
#E=6.63×10^(-34)*(3×10^8)/(460×10^(-9))=4.3×10^(-19)J#

Where:
#f=("speed of light")/("wavelength")#