What volume (in mL) of .158 M KOH solution is needed to titrate 20.0 mL of .0903 M H2SO4 to the equivalance point?

1 Answer
Jul 3, 2017

Answer:

Approx. a #23*mL# volume of the sulfuric acid is required...........

Explanation:

We need (i), a stoichiometric equation.......

#H_2SO_4(aq) + 2KOH(aq) rarr K_2SO_4(aq) + 2H_2O(l)#

And (ii) equivalent quantities of #"sulfuric acid"#,

#"Moles of sulfuric acid"=20.0*cancel(mL)xx10^-3*cancelL*cancel(mL^-1)xx0.0903*mol*cancel(L^-1)=1.806xx10^-3*mol.#

And, CLEARLY, we need #"2 equiv potassium hydroxide......"#

#(2xx1.806xx10^-3*mol)/(0.158*mol*L^-1)xx10^3*mL*L^-1=22.9*mL.#

This is a good question because in the laboratory we would typically LIKE to deal with a titration whose TOTAL volume was around about #50*mL#.