# What volume is occupied by 1.5 moles of oxygen, O_2, gas at STP?

Jul 13, 2018

$33.6$ liters

#### Explanation:

The molar volume of an ideal gas at STP is 22.4 liters/mole

$1.5 \times 22.4 = 33.6$

Jul 13, 2018

$\text{Volume Occupied} = 33.6 {\mathrm{dm}}^{3}$

#### Explanation:

Let the volume occupied be represented by $x$

Since $1.5$ moles of ${O}_{2}$ gas yield $x {\mathrm{dm}}^{3}$ of ${O}_{2}$ gas

Therefore;

$\left(2 \times 16\right) g m o {l}^{-} 1$ of ${O}_{2}$ gas will produce $22.4 {\mathrm{dm}}^{3}$ of ${O}_{2}$ gas

$1$ of ${O}_{2}$ gas will produce $22.4 {\mathrm{dm}}^{3}$ of ${O}_{2}$ gas

$1.5 \to x$

$1 \to 22.4$

Cross multiplying;

$x \times 1 = 1.5 \times 22.4$

$x = 33.6$

Hence;

$\text{Volume Occupied} = 33.6 {\mathrm{dm}}^{3}$