What volume of 0.200 M K2C2O4 is required to completely react with 30.0 mL fo 0.100 M Fe(NO3)3?

1 Answer
May 9, 2017

Answer:

22.5 ml

Explanation:

#sf(2Fe(NO_3)_3+3K_2C_2O_(4)rarrFe_2(C_2O_4)_(3)+6KNO_3)#

The number of moles of #sf(Fe(NO_3)_3)# is given by:

#sf(n=cxxv=0.100xx30.0/1000=3.00xx10^(-3))#

From the equation we can see that the number of moles of #sf(K_2C_2O_(4))# must be 3/2 times this:

#sf(n=3.00xx10^(-3)xx3/2=4.50xx10^(-3))#

#sf(n=cxxv)#

#:.##sf(v=n/c=(4.50xx10^(-3))/(0.200)=22.5xx10^(-3)color(white)(x)L)#

#sf(v=22.5color(white)(x)ml)#