What volume of 0.565 M #K_2CO_3# contains exactly 0.115 moles #K_2CO_3#?

1 Answer
David L.
Apr 12, 2017

#V=0.204# #L# or #20.4# #mL#

Explanation:

The units of molarity are #(mol)/(litre)#, using this information, we can solve for the volume.

#L/(0.565 mol)*0.115 mol#

#L/(0.565 cancel(mol))*0.115 cancel(mol)#

#V=0.115/0.565#

#V=0.204# #L# or #20.4# #mL#

Related questions
See all questions in The Mole
Impact of this question
1516 views around the world
You can reuse this answer
Creative Commons License