# What volume of 1 M sulfuric acid is needed to titrate a 12 ml sample of 0.45 M NaOH?

Jun 4, 2017

A $2.7 \cdot m L$ volume of sulfuric acid is required for equivalence.

#### Explanation:

We need the stoichiometric equation:

${H}_{2} S {O}_{4} \left(a q\right) + 2 N a O H \left(a q\right) \rightarrow N {a}_{2} S {O}_{4} \left(a q\right) + 2 {H}_{2} O \left(l\right)$

And thus we need $\frac{1}{2}$ an equiv of sulfuric acid, i.e.

$\frac{1}{2} \times 12 \times {10}^{-} 3 \cdot L \times 0.45 \cdot m o l \cdot {L}^{-} 1 = 2.7 \times {10}^{-} 3 \cdot m o l$

$\text{Volume"="moles"/"concentration} = \frac{2.7 \times {10}^{-} 3 \cdot m o l}{1 \cdot m o l \cdot {L}^{-} 1}$

$= 2.7 \times {10}^{-} 3 \cdot L = 2.7 \cdot m L$..........