What volume of 7.91M solution of nitric acid, HNO3 is just sufficient to react with 15.9 g of lead dioxide, PbO2 ? 2PbO2 + 4HNO3 ---> 2PbNO3 + 2H20 + O2
First, convert the grams of lead dioxide into moles.
Since for every mole of lead dioxide you need 2 moles of nitric acid, your total moles of needed nitric acid would be:
Seeing that you only have 3 sig figs, the answer would be: