# What volume of nitrogen gas can be produced by the decomposition of 50.0 g of ammonium nitrite if the yield for this reaction is 45.0%? Water is the other product.

##### 1 Answer

#### Answer:

The actual yield using the molar volume

The actual yield using the molar volume

#### Explanation:

Balanced Equation

**Determine moles #"NH"_4"NO"_2"#. The molar mass of ammonium nitrite is #"64.044 g/mol"#.**

We will need the molar volume of a gas for these calculations. Molar volume at the most commonly used values for STP,

**I am keeping an extra digit to reduce rounding errors. I will round to three significant figures at the end.**

Determine moles

**Determine the theoretical volume of #"N"_2"# produced by multiplying by the mole #"N"_2"# by the molar volume of a gas #("22.414 mol/L")#.**

**Convert percent yield to decimal form.**

**Determine actual yield.**

**Multiply the theoretical volume of #"N"_2# by the percent yield.**

The actual yield is

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The most current values for STP, recommended by the International Pure and Applied Chemistry (IUPAC) in 1982, are

**Theoretical yield**

**Actual yield**