# What would be the limiting reactant if 50 grams of sodium cyanide were reacted with 70 grams of copper carbonate?

Apr 26, 2016

$2 N a C \equiv N + C u C {O}_{3} \rightarrow N {a}_{2} C {O}_{3} + C u {\left(C \equiv N\right)}_{2}$

#### Explanation:

From the reaction above, there should 2 equiv of sodium cyanide per equiv of copper carbonate.

$\text{Moles of sodium cyanide}$ $=$ $\frac{50.0 \cdot g}{49.1 \cdot g \cdot m o {l}^{-} 1}$.

$\text{Moles of copper carbonate}$ $=$ $\frac{70.0 \cdot g}{123.56 \cdot g \cdot m o {l}^{-} 1}$.

Given the stoichiometry it is pretty clear as to which reagent is in excess, and which is in deficiency.