# When glucose is consumed, it reacts with oxygen in the body to produce carbon dioxide, water, and energy. How many grams of carbon dioxide would be produced if45 g of C_6H_12O_6 completely reacted with oxygen?

Apr 30, 2017

66 grams $C {O}_{2}$

#### Explanation:

First, find the balanced chemical formula:

${C}_{6} {H}_{12} {O}_{6} + 6 {O}_{2} \rightarrow 6 C {O}_{2} + 6 {H}_{2} O$

Since glucose forms carbon dioxide in a 1:6 ratio, we know that one mole of glucose yields 6 moles of carbon dioxide. So in order to find the moles of carbon dioxide formed, we need to multiply the moles of glucose by 6.

$\text{moles " C_6H_12O_6 = (45g) / "molar mass of glucose}$

$\text{moles } {C}_{6} {H}_{12} {O}_{6} = \frac{45 g}{180.15588 \frac{g}{m o l}}$

$\text{moles } {C}_{6} {H}_{12} {O}_{6} = 0.249783687 m o l s$

$\text{moles } C {O}_{2} = 0.249783687 m o l s \cdot 6$

$\text{moles } C {O}_{2} = 1.498702124 m o l s$

To find grams of carbon dioxide, just multiply the moles of $C {O}_{2}$ by $C {O}_{2}$'s molar mass.

$\text{grams } C {O}_{2} = 1.498702124 m o l s \cdot 44.0095 \frac{g}{m o l}$

$\text{grams } C {O}_{2} = 65.957131124 g r a m s$

Since you only have 2 sig figs, the answer would be 66 grams.