# When the pH of a solution is 12.83, what is [H+]?

Jun 23, 2017

There are $1.479 \times {10}^{-} 13$ concentration of hydrogen ions $m o \frac{l}{L}$.

#### Explanation:

Because pH is a logarthmic scale, we can use the formula: $\left[{H}^{+}\right] = {10}^{\text{-pH}}$. Where...
=> $\left[{H}^{+}\right]$ is the concentration of hydrogen ions in the solution.
=> $p H$ is the pH of the solution.
=> Where $10$ is the base of the power - it's a logarithm formula.

We can now just sub in the values and solve for [H^+].

$\left[{H}^{+}\right] = {10}^{\text{-pH}}$

$= {10}^{- \left(12.83\right)}$

$= 1.479108388 \times {10}^{-} 13$

We can round (if required) to $1.479 \times {10}^{-} 13$.

Thus, there are $1.479 \times {10}^{-} 13$ concentration of hydrogen ions $\frac{m o l}{L}$.

Hope this helps :)