# When the pH of a solution is 12.83, what is [H+]?

##### 1 Answer

Jun 23, 2017

There are

#### Explanation:

Because pH is a logarthmic scale, we can use the formula:

=>

=>

=> Where

We can now just sub in the values and solve for [

#[H^+] = 10^("-pH")#

# = 10^(-(12.83))#

# = 1.479108388 xx 10^-13#

We can round (if required) to

Thus, there are

Hope this helps :)