Where is the vertex for $y= |x/3-4 |$ ?

Question

4280 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2014-10-26T00:25:26

By pulling $1/3$ out of the absolute value sign, we have

$y=1/3|x-12|$ .

Remember that $y=|x|$ has a vertex at $(0,0)$ .

Since vertical shrinkage does not affect the vertex, $y=1/3|x|$ still has a vertex at $(0,0)$ .

By shifting right by 12 units, $y=1/3|x-12|$ has a vertex at $(12,0)$ .

Hence, the vertex is at $(12,0)$ .

I hope that this was helpful.

Where is the vertex for y= |x/3-4 |y= |x/3-4 |?