Which are the solutions to #x^2+9x=36#?

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Answer 1 · 2016-12-08T05:23:14

#x=-12#
#x=3#

#x^2+9x=36#

Subtract 36 from each side:
#x^2+9x-36=0#

Two numbers that multiply to #-36# and add to #9# are: #-3# and #12#

#x^2-3x+12x-36=0#

#x(x-3)+12(x-3)=0#

#(x+12)(x-3)=0#

#x=-12#
#x=3#