Which equivalence factor should you use to convert from 4.25 moles of aluminum (Al) to atoms of aluminum?

1 Answer
anor277
Sep 5, 2016

We use #"Avogadro's number"# to give the number of aluminum atoms.

Explanation:

One mole of stuff specifies #N_A, "Avogadro's number, "# #6.02214xx10^23*mol^-1# individual particles.

We have #4.25*mol#, i.e. #4.25*cancel(mol)xx6.02214xx10^23*cancel(mol^-1)# #"aluminum atoms"#, approx. #25xx10^23# #"aluminum atoms"#. What is the mass of this number of atoms?

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