Which of the following equations is parallel to y = (2/3)x + 6 and contains the point (4, -2)?

1 Answer
May 8, 2018

Answer:

#y=2/3x-14/3#

Explanation:

We know that,

#(1)# If slop line #l_1# is #m_1# and slop of # l_2# is #m_2#, then

#l_1////l_2<=>m_1=m_2#

Here,

#l_1 :y=(2/3)x+6,and l_1////l_2#

Comparing with #y=mx+c#

#=>#Slop of the line #l_1# is #m_1=2/3#

#=>#Slop of the line #l_2# is #m_2=2/3...to[as,m_1=m_2]#

Now, the ' point-slop 'form of line is:

#y-y_1=m(x-x_1)#

For line #l_2#,#m=2/3and #point #(4,-2)#

So,the equation of line is:

#y-(-2)=2/3(x-4)#

#=>3(y+2)=2(x-4)#

#=>3y+6=2x-8#

#=>3y=2x-14#

#=>y=2/3x-14/3#

There is no any equation to compare.!