Which of the following equations would have the roots -½ and ⅗?

(2x - ­ 1)(5x + 3) = 0

(1x + 2)(3x ­- 5) = 0

(2x + 1)(5x - ­ 3) = 0

(1x - ­ 2)(3x + 5) = 0

2 Answers
Shwetank Mauria
Feb 19, 2018

#(2x+1)(5x-3)=0#

Explanation:

If #-1/2# is a root then one factor is #x-(-1/2)# i.e. #x+1/2# or #(2x+1)/2#

and if #3/5# is a root then one factor is #x-3/5# i.e. #(5x-3)/5#

Hence correct answer is #(2x+1)(5x-3)=0# as

#((2x+1)/2)((5x-3)/5)=0hArr(2x+1)(5x-3)=0#

Jim G.
Feb 19, 2018

#(2x+1)(5x-3)#

Explanation:

#"equate each factor in the product on the left to zero and"#
#"solve for x"#

#(2x-1)(5x+3)=0#

#2x-1=0rArrx=1/2#

#5x+3=0rArrx=-3/5#

#"and so on until "#

#(2x+1)(5x-3)=0#

#2x+1=0rArrx=-1/2#

#5x-3=0rArrx=3/5#

#rArr(2x+1)(5x-3)=0" is the equation"#

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