Which orbital do these transition metals are filling in? Sc, Ti, V, Cr?

1 Answer
Aug 11, 2018

Answer:

Well, you are filling the #d-"subshell..."#

Explanation:

For scandium, #Z=21#, we got...#1s^(2)2s^(2)2p^(6)3s^(2)3p^(6)4s^(2)3d^(1)#

For vanadium, #Z=23#, we got...#1s^(2)2s^(2)2p^(6)3s^(2)3p^(6)4s^(2)3d^(3)#

For titanium, #Z=22#, we got...#1s^(2)2s^(2)2p^(6)3s^(2)3p^(6)4s^(2)3d^(2)#

For chromium, #Z=Cr#, #Z=24#, we got...#1s^(2)2s^(2)2p^(6)3s^(2)3p^(6)4s^(2)3d^(4)#

The valence electrons with RESPECT to the atom are the #"d-electrons"#... Upon ionization, we conceive that the #"s-electrons"# are removed first...