# Which point on the parabola #y=x^2# is nearest to (1,0)?

##### 1 Answer

Aug 16, 2015

Approximately

#### Explanation:

I'm just going to solve this by the first method that comes to me, rather than trying to use any special geometric properties of parabolas.

If

To minimize this, we want to minimize

The minimum will occur at a zero of:

graph{2x^3+x-1 [-10, 10, -5, 5]}

Using Cardano's method, find