# Why is pyridine soluble in water, whereas benzene is not?

Pyridine, ${C}_{6} {H}_{5} N$, features a nitrogen centre that is more electronegative than the carbocyclic carbons of the benzene ring. On this nitrogen centre, while the lone pair is delocalized somewhat around the ring, it is still available for H-bonding to the water molecule, and it is quite miscible with water. Benzene has no such heteroatom present, and has very limited water solubility.