Why is the factorization of #2x^2+7x+6=(2x+3)(x+2)?#
If you factor quadratics with #a gt 1# then you have to find factors of #ac# that add to give #b# . So why is the answer #2# and #3# if they don't add to give #7# ?
If you factor quadratics with
1 Answer
Jun 4, 2018
Explanation:
#"given a a quadratic in "color(blue)"standard form ";ax^2+bx+c#
#"to factor consider the factors of ac which sum to b as"#
#"you have stated above"#
#2x^2+7x+6" is in standard form"#
#"with "a=2,b=7" and "c=6#
#"the factors of the product "2xx6=12#
#"which sum to + 7 are + 4 and + 3"#
#"split the middle term using these factors"#
#2x^2+4x+3x+6larrcolor(blue)"factor by grouping"#
#=color(red)(2x)(x+2)color(red)(+3)(x+2)#
#"take out the "color(blue)"common factor "(x+2)#
#=(x+2)(color(red)(2x+3))#
#2x^2+7x+6=(x+2)(2x+3)#