# Why is the oxidation number of oxygen in O_2F_2 +1?

Apr 18, 2017

So when we do this for $\text{FOOF}$ (so-named because of its EXTREME reactivity). We get a formal oxidation states of ""stackrel(-I)F-stackrel(+I)O-stackrel(+I)O-stackrel(-I)F.
What is the oxygen oxidation state in $O {F}_{2}$? Is this usual?