Why #log_(2)^2x(5/(log_(2)3*log_(2)4)+1/log_(2)^(2)5)=0# equal to #log_(2)^2x=0#?
1 Answer
Jun 30, 2018
I tried this:
Explanation:
The entire bit inside the brackets is a number, say,
giving your conclusion in the question;
we can continue and rearrange to write:
using the definitio of log: