# Write a balanced equation for the combustion of liquid penetrate C5H12, in which it combines with gaseous oxygen to form gaseous carbon dioxide and gaseous water?

Jun 16, 2017

${C}_{5} {H}_{12} + 8 {O}_{2} \rightarrow 5 C {O}_{2} + 6 {H}_{2} O$

#### Explanation:

your equation works. However, it is better to use the smallest possible coefficients. Divide your by 2. It still works.

Start by using the 5 carbons in the hydrocarbon to form 5 carbon dioxide. Then use the 12 hydrogens to form 6 waters. Then count up the oxygen atoms needed.

$5 \times {O}_{2} = 10 O$
$6 \times {O}_{1} = 6 O$
= $16 O$
There must be 16 oxygens on the left or reactants to balance the equation. So

$8 \times {O}_{2} = 16 O$

so

$1 \times {C}_{5} {H}_{12} + 8 \times {O}_{2} = 5 \times C {O}_{2} + 6 \times {H}_{2} O$