# Write a nuclear reaction for the neutron-induced fission of U−235 to produce Te−137 and Zr−97. please help?

##### 1 Answer

When uranium-235 undergoes a neutron-induced fission reaction, it will split into two smaller nuclei, which, in your case, are tellurium-137, *neutrons* and *gamma rays* in the process.

So, you know that the uranium-235 nucleus must collide with a neutron, which is a subatomic paticle that has *no electric charge* and a *mass* approximately equal to that of a proton, **1**.

Those will be your rectants.

Isotopes are written in the form

To find the atomic number of each isotope that takes part in the reaction, take a look at a periodic table. Your three isotopes will have

*Uranium-235*#-># #Z = 92# *Tellurium-137*#-># #Z=52# *Zirconium-97*#-># #Z=40#

Now you have what you need to write the nuclear equation.

You can figure out how many neutrons the reaction will release by balancing the mass numbers. On the reactants' side you have **235 + 1**, and on the products' side you have **137 + 97 + ?**.

This means that

The atomic numbers are already balanced, since you have **92 + 0** on the reactants' side, and **52 + 40** on the products' side.

Therefore, the balanced nuclear equation for this reaction is