Question

Write the equation of a circle that has a center of ( 2,-6) and goes through (8,4)?

Answer 1

Equation: `(x-2)^2 + (y+6)^2 = (11.661)^2`

Explanation:

Basic Circle Equation:
`(x-k)^2 + (y-h)^2 = r^2`
Where `(k,h)` is the center.

Therefore,
`r = sqrt((8-2)^2 + (4 + 6)^2)`
`r = 11.661`

Equation: `(x-2)^2 + (y+6)^2 = (11.661)^2`