| ( (x-1)^4, (x-1)^3, (x-1)^2, (x-1), 1 ), ( (x-2)^4, (x-2)^3, (x-2)^2, (x-2), 1 ), ( (x-3)^4, (x-3)^3, (x-3)^2, (x-3), 1 ), ( (x-4)^4, (x-4)^3, (x-4)^2, (x-4), 1 ), ( (x-5)^4, (x-5)^3, (x-5)^2, (x-5), 1 ) | = ?

1 Answer
Feb 9, 2018

288

Explanation:

We seek the value of the determinant, D, where:

D = | ( (x-1)^4, (x-1)^3, (x-1)^2, (x-1), 1 ), ( (x-2)^4, (x-2)^3, (x-2)^2, (x-2), 1 ), ( (x-3)^4, (x-3)^3, (x-3)^2, (x-3), 1 ), ( (x-4)^4, (x-4)^3, (x-4)^2, (x-4), 1 ), ( (x-5)^4, (x-5)^3, (x-5)^2, (x-5), 1 ) |

For Simplicity, write:

x_1=(x-1) , x_2=(x-2) , x_3=(x-3) ,
x_4=(x-4) , x_5=(x-5)

Then we can write the given determinant as:

D = | ( x_1""^4, x_1""^3, x_1""^2, x_1"", 1 ), ( x_2""^4, x_2""^3, x_2""^2, x_2"", 1 ), ( x_3""^4, x_3""^3, x_3""^2, x_3"", 1 ), ( x_4""^4, x_4""^3, x_4""^2, x_4"", 1 ), ( x_5""^4, x_5""^3, x_5""^2, x_5"", 1 ) |

Which is a Vandermonde matrix of order 5. As such we can write the determinant as a product of the factors of the various permutations:

D = prod_(1 le i lt j le n) (x_i-x_j)

\ \ \ = (x_1-x_2)(x_1-x_3)(x_1-x_4)(x_1-x_5) *
\ \ \ \ \ \ \ \ (x_2-x_3)(x_2-x_4)(x_2-x_5) *
\ \ \ \ \ \ \ \ (x_3-x_4)(x_3-x_5) * (x_4-x_5)

\ \ \ = (1)(2)(3)(4) * (1)(2)(3) * (1)(2) * (1)

\ \ \ = (4!)(3!)(2!)

\ \ \ = 24 * 6 * 2

\ \ \ = 288