x(y+4)+y' =0 y(0)=-5 ? separation of variable
1 Answer
Apr 27, 2018
We have:
#y' = -x(y + 4)#
#(y')/(y + 4) = -x#
#ln|y + 4| = -1/2x^2 + C#
#y + 4 = e^(-1/2x^2 + C)#
#y = e^(-1/2x^2 + C) - 4#
We now solve for
#-5 = e^(-1/2(0)^2 + C) - 4#
#-1 = e^C#
But no value of
Hopefully this helps!