# You drive on the freeway between San Francisco and Sacramento at an average speed of 96 km/h (60 mi/h), and the trip takes 2 h and 10 min. On a rainy day you slow down and drive the same distance at an average speed of 80 km/h (50 mi/h). Question: ?

## How much longer does the trip take?

Jun 26, 2018

26 minutes more

#### Explanation:

During the first trip
${V}_{a v} = 96 k m \cdot h {r}^{- 1}$

$t = 2 h r 10 \min = \frac{13}{6} h r$

Total distance travelled(D) is

$\Rightarrow D = {v}_{a v} \cdot t \Rightarrow D = 96 \cdot \frac{13}{6} \Rightarrow D = 208 k m$

During the second trip,
${V}_{a v} = 80 k m \cdot h {r}^{- 1}$

$D = 208 k m$

$t = \frac{D}{V} _ \left(a v\right) \Rightarrow t = \frac{208}{80} \Rightarrow t = 2.6 h r \Rightarrow t = 2 h r 36 \min$

This time is 26 minutes more than previous one.