You have a vinegar solution you believe to be 0.83 M. You are going to titrate 20.0mL of it with a NaOH solution that you know to be 0.519 M. At what volume of added NaOH solution would you expect to see the end point?

1 Answer
May 8, 2017

Answer:

You should expect to see the endpoint at 32 mL of added #"NaOH"#.

Explanation:

Let's write the formula for acetic acid as #"HA"#.

Then the equation for the reaction is

#"HA + NaOH" → "NaA" + "H"_2"O"#.

1. Calculate the moles of #"HA"#

#"Moles of HA" = 0.0200 color(red)(cancel(color(black)("L HA"))) ×( "0.83 mol HA")/(1 color(red)(cancel(color(black)("L HA")))) = "0.0166 mol HA"#

2. Calculate the moles of #"NaOH"#

#"Moles of NaOH" = 0.0166 color(red)(cancel(color(black)("mol HA"))) × ("1 mol NaOH")/(1 color(red)(cancel(color(black)("mol HA")))) = "0.0166 mol NaOH"#

3. Calculate the volume of the #"NaOH"#

#"Volume of NaOH" = 0.0166 color(red)(cancel(color(black)("mol NaOH"))) × ("1 L NaOH")/(0.519 color(red)(cancel(color(black)("mol NaOH")))) = "0.032 L" = "32 mL"#