You place a cup of 205°F coffee on a table in a room that is 72°F, and 10 minutes later, it is 195°F. Approximately how long will it be before the coffee is 180°F?
1 Answer
Approximately
Explanation:
This is a Newton's Law of Cooling Problem.
Newton's Law of Cooling states that an object cools down by the formula
We have to start by finding
#195 = 72 + (205 - 72)e^(-k(10))#
#123/133 = e^(-10k)#
#ln(123/133) = -10k#
#k = -1/10ln(123/133)#
So our formula is
#T(t) = 72 + 133e^(1/10ln(123/133)t)#
We're looking for the amount of time it takes for the coffee to cool to
#180 = 72 + 133e^(1/10ln(123/133)t)#
#108/133 = e^(1/10ln(123/133)t)#
#ln(108/133) = 1/10ln(123/133)t#
A good approximation gives
#t ~~ 26.64#
Therefore, it will take approximately
Hopefully this helps!