Questions asked by Austin M.
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Prove that sec(2theta)=sec^2(theta) divided by (2sec^2(theta))?

A water balloon with a mass of 500 g is launched across a waterpark and lands 150 m away 5 seconds later. What is the initial velocity in the x and y directions, launch angle, and max height?

If the equation given is #y=2x^2# and the point given is (1,2), how would you find the p value from the form #(x0)^2=4p(yk)#?