Answers edited by Jake L.

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• How do you solve #sqrt(2x-6)<4#?
  
• Question #21638
  
• Point A is at #(6 ,2 )# and point B is at #(3 ,-8 )#. Point A is rotated #pi/2 # clockwise about the origin. What are the new coordinates of point A and by how much has the distance between points A and B changed?
  
• How do you find the domain and range of #y = sqrt(x+8)#?
  
• How do you find the amplitude and period of #y = cos 4x#?
  
• I need help on this question as I've been stuck on it for quite a while.! also the range is in radians from 0 TO PI. solve for x? thank you!!
  
• Prove that #(1 + Log_5 8 + Log_5 2)/log_5 6400 = 0.5# Please note the base number of each log is 5 and not 10. I continuously get #1/80#, can someone please assist?