What is the derivative of #y=ln(sec(x))#?
1 Answer
Jul 31, 2014
#y'=tan(x)# Solution
let's
#y=ln(f(x))# differentiating with respective to
#x# via Chain Rule,then,
#y'=1/f(x)*f'(x)# ,Similarly following for the given function,
#y=ln(sec(x))#
#y'=1/sec(x)*sec(x)tan(x)#
#y'=tan(x)#
