How do you write #y+\frac{3}{5}=\frac{2}{3}(x-2) # in standard form?

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Answer 1 · 2014-10-26T12:00:26

#y+3/5=2/3(x-2)#

by multiplying by #15#,
(Note: #15# is the least common multiple of the denominators #5# and #3#.)

#Rightarrow 15y+9=10(x-2)#

by distributing #10# to #x# and #-2#,

#Rightarrow 15y+9=10x-20#

by subtracting #10x# and #9#,

#Rightarrow-10x+15y=-29#

by multiplying by #(-1)#,
(Note: This step is optional since the above is already in standard form.)

#Rightarrow 10x-15y=29#,

which is in standard form.

I hope that this was helpful.