Question

A substance with a mass of 10 kg gains 106.5 kj of heat when its temperature increases 15°c. what is this substance's specific heat?

Answer 1

we know, `Q=mSDeltaT`

here,
Q= 106.5KJ
`DeltaT` = `15^0C`
m = 10kg

so, we have
`106.5 * 10^3` = `10 kg* 15^0C*S`
on re-arranging,
`rArr S = (106.5 * 10^3)/(10*15) J/(kg-C)`
on solving,
`rArr S = 710J/(kg-C)`