How do you write 3(-2a)(-2a)(-2a)(-2a)# in exponential notation?

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Answer 1 · 2014-11-05T15:06:55

#3(-2a)(-2a)(-2a)(-2a)#

since four of the same thing are multiplied together,

#=3(-2a)^4#

by breaking #-2a# into smaller factors,

#=3[(-1)cdot2cdot a]^4#

by distributing the 4th-power,

#=3 cdot (-1)^4 cdot 2^4 cdot a^4#

since #(-1)^4=1#

#=3cdot2^4 cdot a^4#

I hope that this was helpful.