How do you solve #5x-3y=-14# and #x-3y=2# using elimination?

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Answer 1 · 2014-11-05T15:12:16

#{(5x-3y=-14),(x-3y=2):}#

by subtracting the second equation from the first equation,

#=> 4x=-16#

by dividing by 4,

#=> x=-4#.

By plugging #x=-4# into the second equation,

#(-4)-3y=2#

by adding #4#,

#=> -3y=6#

by dividing by #-3#,

#=> y=-2#

Hence, the solution is: #(x,y)=(-4,-2)#.

I hope that this was helpful.