How do you simplify #(-2xy^4z^2)^5#?

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Answer 1 · 2014-12-15T17:43:01

In order to simplify the expression #(-2xy^4z^2)^5# we need to understand that the exponent 5 gets distributed to each term in the parenthesis.

#-2^5x^5y^(4(5))z^(2(5))#

#-2^5# (-2)(-2)(-2)(-2)(-2) = -32

#x^5# = #x^5#

#y^(4(5))# = #y^20#

#z^(2(5))# = #z^10#

Final Answer

#-32x^5y^20z^10#