Question

Question #27f47

Answer 1

The answer is `1.66` `"cm"`

So, start with the fact that you have `2.6 * 10^23` atoms of TI, which will allow you to determine how many moles you actually have

`2.6 * 10^23` `"atoms" * ("1 mole Ti")/("6.022" * 10^23 "atoms") = 0.43` `"moles"`

From here, use `"Ti"`'s molar mass to find out how many grams you have.

`"0.43 moles" * ("47.9 grams")/("1 mole Ti") = "20.6 grams"`

Use the given density to determine the volume you have

`rho = m/V => V = m/(rho) = ("20.6 g")/("4.50 g/cm"^3) = "4.58 cm"^3`

Since you're dealing with a cube, which has a volume of `V_("cube") = "edge"^3`, your edge length will be

`"edge" = V^(1/3) = "1.66 cm"`