How do you solve for f: #f-1+2f+f-3=-4#?

1 Answer
Jan 21, 2015

First of all, let's sum up all terms involving #f# on the left hand, and all numbers as well.

The terms involving #f# are #f+2f+f#, which equals #4f#, while numbers are #-1-3#, which equals #-4#. So far, we can rewrite our equality as
#4f-4=-4#.
Adding 4 on both sides, we get
#4f-4+4=-4+4#, which means
#4f=0#.
Dividing both sides by 4, we have #f=0#.