Question #658ea

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Answer 1 · 2015-01-22T22:30:21

#K=3xx10^5#

#DeltaG=-RTlnK#

#lnK=-(DeltaG)/(RT)#

#lnK=-((-32.5xx10^3)/(8.31xx310))#

#lnK=12.61#

#K=3xx10^5#

Strictly speaking #DeltaG^0# should be under standard conditions. This is at 310K.