How do you find the derivative of y=e^x/xy=exx? Calculus Basic Differentiation Rules Quotient Rule 1 Answer GiĆ³ Feb 10, 2015 You can use the Quotinet Rule where: if y=f(x)/g(x) -> y'=[f'(x)g(x)-f(x)g'(x)]/[g(x)]^2 So you get: y'=(xe^x-1e^x)/x^2= =e^x(x-1)/x^2 Answer link Related questions What is the Quotient Rule for derivatives? How do I use the quotient rule to find the derivative? How do you prove the quotient rule? How do you use the quotient rule to differentiate y=(2x^4-3x)/(4x-1)? How do you use the quotient rule to differentiate y=cos(x)/ln(x)? How do you use the quotient rule to find the derivative of y=tan(x) ? How do you use the quotient rule to find the derivative of y=x/(x^2+1) ? How do you use the quotient rule to find the derivative of y=(e^x+1)/(e^x-1) ? How do you use the quotient rule to find the derivative of y=(x-sqrt(x))/(x^(1/3)) ? How do you use the quotient rule to find the derivative of y=x/(3+e^x) ? See all questions in Quotient Rule Impact of this question 4407 views around the world You can reuse this answer Creative Commons License