Question

How do you differentiate `y=x/(3x-1)`?

Answer 1

I would use the Quotient Rule to get:
`y'=(1*(3x-1)-x*3)/(3x-1)^2=`
`=(3x-1-3x)/(3x-1)^2=`
`=-1/(3x-1)^2`

The Quotient Rule tells you that;
given the function `y=f(x)/g(x)`
The derivative is:
`y'=(f'(x)g(x)-f(x)g'(x))/(g(x))^2`