What is the square root of 50 + the square root of 8?

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What is the square root of 50 + the square root of 8?

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Answer 1 · 2015-03-26T01:40:20

$\sqrt{50} + \sqrt{8} = \sqrt{25 \cdot 2} + \sqrt{4 \cdot 2}$ $sqrt50+sqrt8=sqrt(25*2)+sqrt(4*2)$
$= \sqrt{25} \sqrt{2} + \sqrt{4} \cdot \sqrt{2} = 5 \sqrt{2} + 2 \sqrt{3} = 7 \sqrt{2}$ $=sqrt25sqrt2+sqrt4*sqrt2=5sqrt2+2sqrt3=7sqrt2$ .

Note $\sqrt{50}$ $sqrt50$ is also = $\sqrt{5 \cdot 10}$ $sqrt(5*10)$ but I don't know either of those square roots, so: although it's true, it's not helpful.

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What is the square root of 50 + the square root of 8?

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