What is the domain and range of the function #g(x)=sqrt(x-1)#?

1 Answer
Mar 26, 2015

Hello,

  • The domain of #g# is #[1,+infty[#,
  • The range of #g# is #[0,+infty[#.

Indeed,

  • A real number #x# is in the domain #D# if and only if #sqrt(x-1)# exists, it means #x-1 >= 0#, or #x>=1#. Therefore #D = [1,+oo[#.

  • The range is the set #V# of all the values of the function #g# :

1) Because #g(x) # is a square root, #g(x) >= 0# : therefore, #R subset [0,+oo[#.

2) On the other hand, if #y>= 0#, you can write #y = g(x)# if you consider #x= y^2+1#. Therefore #[0,+oo[ subset R# and finally #R= [0,+oo[#.

Graphically :

Domain is the projection of the curve of #g# on x-axes
Range is the projection of the curve of #g# on y-axes

graph{sqrt(x-1) [-1.75, 18.25, -1.88, 8.12]}