Question

How do you solve `6x^2+ 7x - 20 = 0` by factoring?

Answer 1

`6x^2 + 7x -20 = 0`
is a quadratic of the form
`ax^2 + bx + c = 0`
which is solved using the formula
`x = (-b +- sqrt(b^2 - 4ac))/(2a)`
I would recommend chanting this formula as many times as necessary to remember it forever; this formula will keep showing up.

For the given equation we have
`x = (-7 +-sqrt(49+480))/(12)`

`x = (-7 +- 23)/(12)`

So (after simplifying) the solutions to the given equations are
`x = (15)/6` and `x = 4/3`