How do you find the derivative of #e^(1/(2x))#? Calculus Differentiating Exponential Functions Differentiating Exponential Functions with Base e 1 Answer Jim H Mar 30, 2015 Use #d/(dx)(e^x)=e^x# togerther with the chain rule to see that: #d/(dx)(e^(1/(2x)))=e^(1/(2x))*d/(dx)( 1/(2x))# #=e^(1/(2x))* (-1/(2x^2))= -e^(1/(2x))/(2x^2)# Answer link Related questions What is the derivative of #y=3x^2e^(5x)# ? What is the derivative of #y=e^(3-2x)# ? What is the derivative of #f(theta)=e^(sin2theta)# ? What is the derivative of #f(x)=(e^(1/x))/x^2# ? What is the derivative of #f(x)=e^(pix)*cos(6x)# ? What is the derivative of #f(x)=x^4*e^sqrt(x)# ? What is the derivative of #f(x)=e^(-6x)+e# ? How do you find the derivative of #y=e^x#? How do you find the derivative of #y=e^(1/x)#? How do you find the derivative of #y=e^(2x)#? See all questions in Differentiating Exponential Functions with Base e Impact of this question 15215 views around the world You can reuse this answer Creative Commons License