How do you find the slope of the line whose equation is #2x – 4y = 10#?

2 Answers
Mar 31, 2015

Yo can rearrange your equation and "see" you slope as coeficient of #x#:
isolating #y# you have:
#y=1/2x-5/2#

So your slope is #1/2#

Mar 31, 2015

The slope of the line is #1/2#.

The equation of a line in slope-intercept form is #y=mx + b#, where #m# is the slope, #b# is the y-intercept, and #x# and #y# are a point on the line.

In order to determine the slope from the given equation, do the following:

#2x - 4y = 10# (Subtract #2x# from both sides.)

#-4y = -2x + 10# (Divide both sides by -4.)

#y = (-2x)/(-4) + (10)/(-4)# (Simplify.)

#y = 1/2 x - (5)/(2)#