Question

How do you find the standard form and slope intercept of a line that passes through (4,1) parallel to `y=-5`?

Answer 1

`y=-5` has a slope of `0` since the change in `y` is `0` regardless of the change in `x`

The equation of the line passing through `(4,1)` parallel to `y=-5` (that is, with slope `= 0`)
is `y=1`.

`y=1` is its "standard form".