How do you solve the system of equations 2x+3y=6 and 3x+3y=14?

1 Answer
Apr 1, 2015

x = 8, y = -10/3

Our aim is finding a similarity in the two equations. In this problem, we already have it: 3y

So, lets rewrite the second equation:

2) 3x + 3y = 14
3y = 14 - 3x

Now, we can replace 3y with 14-3x in the first equation.

2x + (14-3x)=6
2x+14-3x=6
-x=-8
x = 8

Now, we know the value of x. By using either first or second equation we can calculate the value of y. Lets use the second "2)" equation.

2) 3x + 3y = 14
3*8 + 3y = 14
24+3y=14
3y = -10
y=-10/3